A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a soluti

Question

A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 3.5 × 10–4 M in calcium ion and 2.33 × 10–4 M in oxalate ion. What will happen once these solutions are mixed? Ksp (CaC2O4) = 2.3 × 10^–9.

A. Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds.

B. Nothing will happen Ksp > Q for all possible precipitants.

C. A precipitate will form as calcium oxalate is not soluble to any extent.

D. A precipitate will form since Q > Ksp for calcium oxalate.

Explanation / Answer

Calcium oxalate is sparingly soluble salt. Therefore, if ionic product of Ca2+ and C2O42- exceeds the Ksp value, it will start to precipitate as CaC2O4 (s).

Ksp (CaC2O4) = 2.3 × 10–9.

[Ca2+]= 3.5 × 10–4 M ; [C2O42-] = 2.33 × 10–4 M

Ionic product Q of Ca2+ and C2O42- = [Ca2+] [C2O42-] = 3.5 × 10–4 * 2.33 × 10–4 = 8.155 * 10-8

Value of Ionic product Q of Ca2+ and C2O42- exceedingthe value of Ksp; Q > Ksp

therefore Ions will starts to precipiates.

Answer- D------->A precipitate will form since Q > Ksp for calcium oxalate.

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