A solution containing CaCl2 is mixed with a solution of Li2CO3 to form a solutio
ID: 936513 • Letter: A
Question
A solution containing CaCl2 is mixed with a solution of Li2CO3 to form a solution that is 2.1 x 10-5 M in calcium ion and 4.75 x 10-5 M in carbonate ion. What will happen once these solutions are mixed?
Nothing will happen since calcium carbonate is extremely soluble
Nothing will happen since both calcium chloride and lithium carbonate are soluble compounds
A precipitate will form
Nothing will happen since Ksp > Q for all possible precipitates
Nothing will happen since calcium carbonate is extremely soluble
Nothing will happen since both calcium chloride and lithium carbonate are soluble compounds
A precipitate will form
Nothing will happen since Ksp > Q for all possible precipitates
Explanation / Answer
Given that CaCl2(aq) + Li2CO3(aq) --------------> 2LiCl(aq) + CaCO3(s)
CaCO3 <------------> Ca^2+ + CO3^2-
Qsp = [Ca^2+] [CO3^2-]
Q sp = [2.1 x 10^-5] [4.75 x 10^-5]
Qsp = 9.97 x 10^-10
But, Actual Ksp of CaCO3 is 4.8 x 10^-9
As, Ksp > Q, last option is correct.
Nothing will happen since Ksp > Q for all possible precipitates.
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