A.) Find the standard reduction potential, E°, for the dissolution reaction : Zn

Question

A.) Find the standard reduction potential, E°, for the dissolution reaction : Zn(OH)2 (s) <-----> Zn2+ (aq) + 2 OH- (aq)
B.) find the Solubility product , K sp
How do I determine which is the E+ and which is E- when trying to solve for E°?? A.) Find the standard reduction potential, E°, for the dissolution reaction : Zn(OH)2 (s) <-----> Zn2+ (aq) + 2 OH- (aq)
B.) find the Solubility product , K sp
How do I determine which is the E+ and which is E- when trying to solve for E°?? Zn(OH)2 (s) <-----> Zn2+ (aq) + 2 OH- (aq)
B.) find the Solubility product , K sp
How do I determine which is the E+ and which is E- when trying to solve for E°??

Explanation / Answer

Zn ---> Zn2+ + 2e E0 = +0.793 V

Add the two together and you get the Ksp expression, and the voltage is -0.452V.

You then can use the combination of two equations, which equate Gibbs free energy to potential, and to equilibrium constant, to get:

nFE = RT ln K

Ksp would then be equal to e(nFE/RT). Use 298 K for T, n = 2, 96500 for F, and 8.314 for R, and you should get 5.1 x 10^-16 (a little off from the accepted value of 1.2 x 10^-17).

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