Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A disproportionation reaction is an oxidation-reduction reaction in which the sa

ID: 857238 • Letter: A

Question

A disproportionation reaction is an oxidation-reduction reaction in which the same substance is oxidized and reduced. Complete and balance the following disproportionation reactions.

A. Ni+(aq)?Ni2+(aq)+Ni(s) (acidic solution)

Express your answer as a chemical equation. Identify all of the phases in your answer.

B. MnO2?4(aq)?MnO?4(aq)+MnO2(s) (acidic solution)

Express your answer as a chemical equation. Identify all of the phases in your answer.

C. H2SO3(aq)?S(s)+HSO?4(aq) (acidic solution)

Express your answer as a chemical equation. Identify all of the phases in your answer.

D. Cl2(aq)?Cl?(aq)+ClO?(aq) (basic solution)

Express your answer as a chemical equation. Identify all of the phases in your answer

Explanation / Answer

(a) Write the two half reactions. Multiply them to make electrons lost equal electrons gained. Addemall up.

Ni+ + e- ===> Ni

Ni+ ===> Ni2+ + e-

2Ni+ ===> Ni + Ni2+

D. Same as before. When writing the second half reaction, add OH- to one side and and H2O to the other to make the atoms and charges balance.

Cl2 + 2e- ===> 2Cl-

4OH- + Cl2 ===> 2ClO- + 2e- + 2H2O

4OH- + 2Cl2 ===> 2Cl- + 2ClO- + 2H2O

B.

2 I- = I2 + 2e-
MnO4- + 4 H+ + 3e- = MnO2 + 2 H2O

6 I- + 2 MnO4- + 8 H+ = 3 I2 + 2 MnO2 + 4 H2O

add 8 OH- on the left and on the right

6 I- + 2 MnO4- + 4 H2O = 3 I2 + 2 MnO2 + 8 OH-

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote