The gunpowder reaction can be written as 10 KNO3(s) + 11C(s) + 4 S(s) ? 5 CO(g)

Question

The gunpowder reaction can be written as

10 KNO3(s) + 11C(s) + 4 S(s)

                       ?

5 CO(g) + 5CO2(g) + 5 N2(g) + K2CO3(s) + 3K2SO4(s) + K2S(s)

Part A - If you run the gunpowder reaction with 40 molecules of saltpeter (KNO3) , 44 atoms of carbon, and 16 atoms of sulfur, how many molecules of nitrogen will you produce?

Part B - If you run the gunpowder reaction with 40 molecules of saltpeter (KNO3) , 44 atoms of carbon, and 16 atoms of sulfur, how many molecules of carbon dioxide will you produce?

Part C - If you run the gunpowder reaction with 40 molecules of saltpeter (KNO3) , 44 atoms of carbon, and 16 atoms of sulfur, how many molecules of carbon monoxide will you produce?

Explanation / Answer

Just multiply all coefficients of the balanced equation by 4. Then you will get 40 molecules of saltpeter (KNO3) , 44 atoms of carbon, and 16 atoms of sulfur on the reactant side. At the same time, you will get the following in the product side:

A) 20 molecules of nitrogen

B) 20 molecules of carbon dioxide

C) 20 molecules of carbon monoxide

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