Given: Experiment 1: NaHCO3= 0.0095238 mol CH3COOH=0.025 mol CO2=135.2 mL=0.1352

Question

Given:

Experiment 1: NaHCO3= 0.0095238 mol CH3COOH=0.025 mol CO2=135.2 mL=0.1352 L=0.0060 mol

Experiment 2: NaHCO3=0.01905 mol CH3COOH=0.025 mol CO2 = 233.63 mL=0.23363 L=0.0104 mol

Experiment 3: NaHCO3= 2.4 g=0.02857143 mol CH3COOH =0.025 mol CO2=297.03 mL=0.29703 L=0.0133 mol

Experiment 4: NaHCO3=0.0381 mol CH3COOH=0.025 mol CO2=456.3 mL=0.4563 L=0.0204 mol

1. Write out the balanced equation:

2. Which combo of ingredients (1,2,3,4) produced the greatest amount of product (CO2)?

3. Which experiment had NaHCO3 as the limiting reactant? Which had CH3COOH as the limiting reactant?

4. Why is comparing moles of reactant without using the balanced equation not the proper way to determine the limiting agent?

5. Why did one reaction situation produce the greatest volume of CO2?

Explanation / Answer

1. Balanced equation for the above experiment is

NaHCO3 + CH3COOH ? CH3COONa + H2O + CO2

2. Ingredients of experment no.4 produced the greatest amount of product CO2

3.Experiment no. 1 & 2 had NaHCO3 as limiting reagent . Experiment No. 3 & 4 had CH3COOH as limiting reagent.

4."limiting reagnet", is the substance which is totally consumed when the chemical reaction is complete. Only from balanced equation we truly know if the given compound is in excess or less. If the reaction is not balanced we will never know the true amount required for the given reaction to happen.

5.Experiment 5 gives us the greatest volume of CO2 because both NaHCO3 and CH3COOH are in excess compared to other experiments.

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