Given: F(x) = Square Root of x2 +4 G(x) = (x-1) Find {G[F(x)]}2 I worked out G o

Question

Given:



F(x) = Square Root of x2 +4

G(x) = (x-1)



Find {G[F(x)]}2



I worked out G of F(x) = [(Square Root x2 +4) -1]2



So if you square the square root, and square the "1", then



the answer is x2 + 3... Is this correct????

Given: F(x) = Square Root of x2 +4 G(x) = (x-1) Find {G[F(x)]}2 I worked out G of F(x) = [(Square Root x2 +4) -1]2



So if you square the square root, and square the "1", then



the answer is x2 + 3... Is this correct????

So if you square the square root, and square the "1", then the answer is x2 + 3... Is this correct????

Explanation / Answer

If you're never sure, use a random value for x to check your work. In this case if x=6: [(SR(6)(2)+4)-1](2) (SR16-1)(2) (4-1)2 (3)(2) =6 AND you're answer x2+3 (6)(2)+3 =15 So the answer you got is incorrect. You cannot square one side without squaring the other side {[SR(2x+4)-1]*2} so the answer is simply 2SR(2x+4)-2

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