Given: 4 KO2(s) + 2 CO2(g) 2 K2CO3(s) + 3 O2(g). Submarine design teams were inv

Question

Given: 4 KO2(s) + 2 CO2(g) 2 K2CO3(s) + 3 O2(g). Submarine design teams were investigating the use of KO2 to purify the air in small submarines. Calculate the mass of KO2 needed to react with 50.0 L of carbon dioxide at -10.0 °C and 1.13 atm pressure. Given: 4 KO2(s) + 2 CO2(g) 2 K2CO3(s) + 3 O2(g). Submarine design teams were investigating the use of KO2 to purify the air in small submarines. Calculate the mass of KO2 needed to react with 50.0 L of carbon dioxide at -10.0 °C and 1.13 atm pressure.

Explanation / Answer

Assume CO is ideal gas and calculate moles of CO

n= PV/RT = 1.13*50 /0.082*263. = 2.62 moles

4 moles KO2 is required for 2 moles of CO

So here we require 2*2.62 moles = 5.24 moles

Molar mass of KO2 = 71.10 g/mol

So mass of KO2 = 71.10*5.24 moles = 372 grams

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