Ammonia is produced from the reaction of nitrogen and hydrogen according to the
ID: 823667 • Letter: A
Question
Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation:
N2(g) + 3H2(g) ? 2NH3(g)
1. What is the maximum mass of ammonia that can be produced from a mixture of 163.3 g of N2 and 38.77 g of H2? g
2. Which element would be completely consumed? (enter nitrogen or hydrogen)
3. What mass of the starting material would remain unreacted? g
Watch the mole ratios!
Whichever produces the smallest amount of ammonia is the limiting reactant.
HINT: After you have found which starting material was used up completely, you know that some of the
other starting material is still unreacted. Subtract the reacted material (which you must calculate) from the
original amount you had in the beginning, thus finding how much remains unreacted.
Watch the mole ratios!
Whichever produces the smallest amount of ammonia is the limiting reactant.
HINT: After you have found which starting material was used up completely, you know that some of the
other starting material is still unreacted. Subtract the reacted material (which you must calculate) from the
original amount you had in the beginning, thus finding how much remains unreacted.
Explanation / Answer
1. & 2.
(163.3 g N2) / (28.01344 g N2/mol) = 5.829 mol N2
(38.77 g H2) / (2.015894 g H2/mol) = 19.24 mol H2
6.85742 moles of N2 would react completely with 5.83 x (3/1) = 17.49 moles of H2, but there is more H2 present than that, so H2 is in excess and N2 is the limiting reactant, which is to say that the N2 will be completely consumed.
(5.83 mol N2) x (2 mol NH3 / 1 mol N2) x (17.03056 g NH3/mol) = 198.57 g NH3
3.
((19.24 mol H2 initially) - (17.49mol H2 reacted)) x (2.015894 g H2/mol) =
3.5 g H2 unreacted
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