Ammonia and oxygen react to form nitrogen and water, like this: 4 NH3(g)+3O2(g)

Question

Ammonia and oxygen react to form nitrogen and water, like this: 4 NH3(g)+3O2(g) 2 N2(g) +6H2O(g) Use this chemical equation to answer the questions in the table belovw None Suppose 185. mmol of NH3 and 139. mmol of O2 are added to an empty flask. How much N2 will be in the flask at equilibrium? Suppose 110. mmol of N2 and 330. mmol of H2O are added to an empty flask. How much N2 will be in the flask at equilibrium? OSome, but less than 92.5 mmol 92.5 mmol. More than 92.5 mmol. O None. Some, but less than 220. mmol. 220. mmol. More than 220. mmo

Explanation / Answer

     4 NH3(g) + 3O2(g) -------------> 2N2(g) + 6H2O(l)

3 moles of O2 react with 4 moles of NH3
   139 mmoles of O2 react with = 4*139/3 = 185.3 mmoles of NH3 is required
         NH3 is limiting reactant
   4 moles of NH3 react with O2 to gives 2 moles of N2
   185 mmoles of Nh3 react with O2 to gives = 2*185/4 = 92.5 mmoles of N2 >>>>answer

from balanced equation

2 moles of N2 react with 6 moles of H2O

110 mmoles of N2 react with = 6*110/2   = 330 mmoles of H2O

zero mmoles of N2 is present at equilibrium

none >>>.answer

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