How many molecules of carbon dioxide are produced when 1 x 1024 molecules of oct
ID: 799521 • Letter: H
Question
How many molecules of carbon dioxide are produced when 1 x 1024 molecules of octane are combusted (use your previously balanced chemical equation for the combustion of octane #1).
What mass of carbon dioxide is produced when 1 x 1024 molecules of octane are combusted (use your previously balanced chemical equation for the combustion of octane #1).
How many carbon dioxide molecules are produced for every gram of octane combusted (use your previously balanced chemical equation for the combustion of octane #1)?
Limiting Reactants and Theoretical Yield
Suppose you are going on a picnic and you are bringing sandwiches. You find all the ingredients that you have in your kitchen and your goal is to make as many sandwiches as you can.
You find:
26 slices of bread
14 pieces of meat
3 tomatoes
16 leaves of lettuce
15 pieces of cheese
You want to make your sandwiches with 2 slices of bread, 1 piece of meat, 1 pieces of cheese, 2 slices of tomato (each tomato can be sliced into 9 slices) and 1 leaf of lettuce.
How many sandwiches can you make?
Explanation / Answer
1)
6.023*10^23------------------------------------1mole of octane
1024 molecule of octane----------------------------------?
=1024/6.023*10^23=170.01*10^-23moles
1 mole of ocatne gives--------------------------------------------------------8 *6.023*10^23co2 molecules
170.01*10^-23 moles------------------------------------------------------?
=170.01*10^-23*8*6.023*10^23
=1360.11*6.023
2168.94 co2molecules are produced
2) one co2 molecule--------------------------44 gram
2168.94CO2 MOLECULES------------------/
=2168.94*44
=95433.47 GRAMS OF CO2
3)114 grams of octane gives------------------------8 *6.023*10^23 CO2 MOLECULES
1 gram of octane-----------------------------?
=8/114
=4.22*10^22 co2 molecules
4)13 sanwitches
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.