Two charges are placed on the x axis. One of the charges (q1 = +8.56C) is at x1
ID: 778326 • Letter: T
Question
Two charges are placed on the x axis. One of the charges (q1 = +8.56C) is at x1 = +3.00 cm and the other (q2 = -23.1C) is at x2 = +9.00 cm. Find the net electric field (magnitude and direction given as a plus or minus sign) at (a) x = 0 cm and (b) x = +6.00 cm.
(magnitude and direction given as a plus or minus sign) at (a) x =0 cm and (b) x-+6.00 cm. Units N/C Units N/C Two charges are placed on the x axis. One of the charges (1 +8.56Hc) is at x1 +3.00 cm and the other (02--23.1C) is at x2-+9.00 cm. Find the net electric field (a) Number 1[18154805.56 (b) Number59866740.74Explanation / Answer
we know that
Electric field = kQ/R^2
direction is towards the negative charge and away from positive charge.
A.
At x = 0 cm, due to q1, E will be towards -ve x-axis and due to q2, E will be towards +ve x-axis
Enet = E2 - E1
Enet = kq2/r2^2 - kq1/r1^2
using know values:
r2 = 9 cm, r1 = 3 cm
Enet = 9*10^9*23.1*10^-6/0.09^2 - 9*10^9*8.56*10^-6/0.03^2
Enet = -5.99*10^7 N/C
B.
At x = 6 cm, due to q1, E will be towards +ve x-axis and due to q2, E will be towards +ve x-axis
Enet = E2 + E1
Enet = kq2/r2^2 + kq1/r1^2
using know values:
r2 = 3 cm, r1 = 3 cm
Enet = 9*10^9*23.1*10^-6/0.03^2 + 9*10^9*8.56*10^-6/0.03^2
Enet = +31.66*10^7 N/C
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