Two charged objects exert a 4.8-N force on each other when separated by 1.0 m .

Question

Two charged objects exert a 4.8-N force on each other when separated by 1.0 m .

Part A

Find the product of the two charges.

Express your answer using two significant figures.

Part B

Determine the force that one charged object exerts on the other when the separation is doubled.

Express your answer to two significant figures and include the appropriate units.

Part C

Determine the force that one charged object exerts on the other when the separation is reduced by one-half.

Express your answer to two significant figures and include the appropriate units.

Part D

Determine the force that one charged object exerts on the other when the magnitude of one charge is reduced by one-half.

Express your answer to two significant figures and include the appropriate units.

Part E

Determine the force that one charged object exerts on the other when both charges are doubled.

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Here ,

force acting , F = 4.8 N

distance , d = 1 m

A)

the force between two charges is given as

F = k*|q1||q2|/d^2

4.8 = 9*10^9 |q1||q2|/1

|q1||q2| = 5.33 *10^-10 C^2

the product is |q1||q2| is 5.33 *10^-10 C^2

B)

for the double distance ,

Fnew = F/2^2

Fnew = 4.8/4

Fnew = 1.2 N

the new force between the particle is 1.2 N

C)

for half the seperation ,

Fnew = F/(0.5)^2

Fnew = 4.8/(0.5)^2

Fnew = 19.2 N

the new force is 19.2 N

D)

if one chagre is reduced by half

Fnew = 0.5 * F

Fnew = 0.5 * 4.8

Fnew = 2.4 N

the new force is 2.4 N

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