Two charged objects are separated by a distance of L=0.7580 m as shown in the di

Question

Two charged objects are separated by a distance of L=0.7580 m as shown in the diagram.

Object Q1 has a charge of +6.940 nC. Object Q2 has a charge of +2.040 nC.
What is the magnitude and direction of the electric field at Point A, which is located a distance d=0.2047 m to the right of Object Q1?

to the Left to the Right Two charged objects are separated by a distance of L=0.7580 m as shown in the diagram. Object Q1 has a charge of +6.940 nC. Object Q2 has a charge of +2.040 nC. What is the magnitude and direction of the electric field at Point A, which is located a distance d=0.2047 m to the right of Object Q1? If you were to place an electron at Point A, what would be the magnitude and direction of the force on the electron?

Explanation / Answer

E = kq/r^2 = 8.89*10^9*((6.94*10^-9/(0.2047^2)) - (2.040*10^-9/((0.758-0.2047)^2))) = 1413.1597180681 N/m to the right

force on electron = E*q = 1413.1597180681*1.6*10^-19 = 2.26105554890896*10^-16 N to the left

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