My Notes Ask Your Teach 1.32/2 points 1 Previous Answers SerCP9 21 P020 MI.FB An

Question

My Notes Ask Your Teach 1.32/2 points 1 Previous Answers SerCP9 21 P020 MI.FB An inductor (1-400 mH), a capacitor (C-4.43 F), and a resistor (R-S00 O) are connected in series. A 52.0-Hz AC generator corrected in series to these elements produces a maximum current of 355 mA in the circuit. (a) Calculate the required maximum voltage Arax. 266.6 (b) Determine the phase angle by which the current leads or lags the applied voltage. The current leads the voltage by a magnitude of -1798X Apply the expression for the phase angle in terms of the resistance, ductance, and capacitance

Explanation / Answer

Impedance Z = 750.99 ohm

Resistance R = 500 ohm

Let phi be the phase angle. Then we have:

cos(phi) = R/Z

=> phi = cos-1(500/750.99)

= 48.26 degrees

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