What is the free energy change, G, associated with thefollowing electrochemical

Question

What is the free energy change, G, associated with thefollowing electrochemical reaction in kJ/mol? Zn(s) + Cu2+(aq) -> Zn2+ (aq) +Cu(s) Thanks! What is the free energy change, G, associated with thefollowing electrochemical reaction in kJ/mol? Zn(s) + Cu2+(aq) -> Zn2+ (aq) +Cu(s) Thanks!

Explanation / Answer

Zn(s)          -> Zn2+ +2e-           E = +0.7618 Cu2+ + 2?e- ->Cu(s)                    E = +0.340 --------------------------------------------------- Zn(s) + Cu2+(aq) -> Zn2+ (aq) +Cu(s)          E0= 0.7618+0.340 = 1.1018 V delG = -nFE0 n = 2 (electrons transferred) F = 96485 C/mol delG = (2*96485 C/mol) * (1.1018 V) = 212614.346 J/mol = -212.6kJ/mol EDIT: negative sign

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