What is the final velocity of car 2 in the ground (original) reference frame? A

Question

What is the final velocity of car 2 in the ground (original) reference frame? A bumper car with mass m1 = 104 kg is moving to the right with a velocity of v1 = 4.2 m/s .A second bumper car with mass m2 = 97 kg is moving to the left with a velocity of v2 = -3.9 m/s. The two cars have an elastic collision . Assume the surface is frictionless.

Explanation / Answer

suppose after collision m1 moves with velocity v1 rigthward..... & m2 moves with velocity v2 rightward..... applying conservation of momentum 104x(4.2) - 97x(3.9) = 104x(v1) + 97x(v2)- - - - - - -> equation 1 applying coefficient of restitution = (velocity of separation/velocity of approach) 1 = (v2 - v1)/(4.2+3.9) - - - - - -> equation 2 solving v2 = 4.48 m/s

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