A hiker caught in a rainstorm might absorb 1 liter of water in his cloths. if it

Question

A hiker caught in a rainstorm might absorb 1 liter of water in his cloths. if it is winding so that this amount of water evaporates at 20 degrees celcius how much heat would be required for this process? please include a equation that you derived the answer from and some explinations thanx

Explanation / Answer

I know that you do not rate any answers (as your rating percentage is showing 0, but still i am helping you) Specific heat of water = 4.184 J/g/C And, Heat of vaporization of water = 2260 J/g density of water = 1 g/cm^3 And, 1 litre = 1000 cm^3 => mass of water given = volume * density = 1000*1 = 1000 grams heat required for water to reach 100 degree C = 1000*4.184*(100-20) = 334720 Joules = 334.72 KJ Heat required in vaporization of water = 1000*2260 = 2260000 J = 2260 KJ => total heat required = 2260+334.72 = 2594.72 KJ

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