My balanced equation is: 3HBr(aq) + Al(OH)3 (s) ----> AlBr3 (aq) + 3H2O(l) My qu

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Al(OH)3(s) + 3HBr(aq) ==> AlBr3(aq) + 3H2O(l) First split into ions any strong electrolytes. That would be HBr and AlBr3 (which is soluble). We do NOT split up the solid Al(OH)3 or the pure liquid H2O. Al(OH)3(s) + 3H+(aq) + 3Br-(aq) ==> Al3+(aq) + 3Br-(aq) + 3H2O(l) Cancel 3Br- from both sides of the equation; Br- is a spectator ion that doesn't react. Al(OH)3(s) + 3H+(aq) ==> Al3+(aq) + 3H2O(l) . .

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