How do you find part c? A voltaic cell has one half-cell with a Cu bar in a 1.00

Question

How do you find part c?

A voltaic cell has one half-cell with a Cu bar in a 1.00 M Cu2+ salt and the other half-cell with a Cd bar in the same volume of a 1.00 M Cd2+ salt. Find E degree cell, delta G degree , and K. Report your answers to the correct number of significant figures. E degree cell = 0.737 V delta G degree = -1. 42 .times 105 J K = 7.92 times 1024 As the cell operates, [Cd2+] increases; find E cell when [Cd2+] is 1.95 M. E cell = 0.728 V Find E cell, delta G, and [Cu2+] at equilibrium. E cell = 0-737 V delta = -142000 J [Cu2+] = times M

Explanation / Answer

Ecell = E0cell - (RT/nF)lnQ

0.728 = 0.737 -(0.059/2)lnQ

lnQ = 0.305

Q = 1.357 = [Cd2+]/[Cu2+]

[Cu2+] = 1.95/1.357 = 1.437 M

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