How do you do A & B? 17. 113 points | Previous Answers My Notes Ask Your Teacher

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How do you do A & B?

17. 113 points | Previous Answers My Notes Ask Your Teacher The proportion of men in the population who have prostate cancer is 35 per 100,000. In 1980, a new test was developed to test for the presence of prostate cancer. The researchers who developed the test wanted to know the probability that a man who tested positive for prostate cancer actually had the disease. To find this probability, they took a random sample of 99 men known to have prostate cancer and another random sample of 150 men known not to have prostate cancer (after having a biopsy). Their test is a radioimmunoassay for prostate acid phosphatase (RIA-PAP). They found the following results (real data) Test Result Negative Positive Total Cancer ancer 139 150 Has Cancer 30 169 69 80 Total 249 Let C = a randomly selected man has prostate cancer Use 3 decimal places. (a) P(C I Pos)-0.863 (b) P(C I Pos) - (c) Can you use the table above to find P(C), the probability a randomly chosen male selected from the entire male population has prostate cancer? O Yes, because it was an experiment. O No, because it was an observational study O Yes, because the sample was taken randomly No, because the percentage of patients in the study with cancer is not representative of the percentage of people in the population with cancer

Explanation / Answer

a) P(C/POs) = 69/80 = 0.863

b)  P(C'/POs) = 11/80 = 0.138

c) Option D is Correct

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