Glucose (C 6 H 12 O 6 ) can be broken down into ethyl alcohol (C 2 H 5 OH) and c

Question

Glucose (C6H12O6) can be broken down into ethyl alcohol (C2H5OH) and carbon dioxide gas (CO2) according to the following balanced chemical equation:

C6H12O6(aq)   ?   2 C2H5OH(aq) + 2 CO2(g)

Calculate the mass of each product if 45.50 g of glucose decomposes completely. The molar masses of all three substances have been provided below to help expedite your calculations.

Mm C6H12O6 = 180.16 g/mol
Mm C2H5OH = 46.07 g/mol
Mm CO2 = 44.01 g/mol

_____ grams of C2H5OH will be produced upon the complete decomposition of 45.50 g C6H12O6.
_____ grams of CO2 will be produced upon the complete decomposition of 45.50 g C6H12O6.

Explanation / Answer

Mass of glucose = 45.5g

No of moles of glucose = 45.5/180.16= 0.2525 gmol

From above balanced equation

1 mol glucose decompose will give 1 mol ethanol and 2mol CO2

0.2525 moles glucose will produce 0.2525 moles ethanol and 0.5050 (2*0.2525) moles CO2

So

grams of ethanol produced = 0.2525×46.07= 11.633g

grams of CO2 produced. = 0.5050×44.01= 22.23g

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