3. A solution of Th(NO,), a frezing point depression o of 9.6 mmol/kg. K, = 0.51

Question

3. A solution of Th(NO,), a frezing point depression o of 9.6 mmol/kg. K, = 0.51 K/m, K,-186K/m (a) Write down the solubility reaction of Th(NO,) of 0.0703 K was observed for an aqueous solution of molality . How many ions are produced by one formula unit? (b) What should have been the theoretical freezing point of the solution (e) What is the experimental mumber of ions per formula unit? (d) Predict the boiling point of the solution that would be consistent with the experiment. (e) Predict the osmotic pressure of the solution at 298K. Assume density of solution is 1.00

Explanation / Answer

Part a

Solubility reaction

Th(NO3)4 = Th4+ + 4NO3-

Total ions produced = 1 + 4 = 5

Part b

Freezing point of solution

Tf - Ts = i x Kf x m

273 - Ts = 5 x 0.51 x 9.6*10^-3

Ts = - 0.02448 °C = freezing point of solution

Part c

Experimental number of ions

i = freezing point depression / kf x m

= 0.0703 K / 0.51 x 9.6*10^-3

= 14.35

Part d

Ts - Tb = i x Kb x m

Ts = 100 + 14.35 x 1.86 x 9.6*10^-3

Ts = 100.256 °C = boiling point of solution

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