Map Sapling Learning The following is a multi-step reaction. The rate-limiting s

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Map Sapling Learning The following is a multi-step reaction. The rate-limiting step is unimolecular, with A as the sole reactant. A+B C+ D If [A] and [B] are both 0.120 M, then the rate of reaction is 0.0090 M/s. (a) What is the rate of the reaction if [A] is doubled? Number M/s (b) Starting with the original concentrations, what is the rate of the reaction if [B] is doubled? Number M/s (c) Starting with the original concentrations, what is the rate of the reaction if [A] and [B] are both increased by a factor of four? Number M/s Previous Give Up & View Solution O Check AnswerNext Exit Hint

Explanation / Answer

Given reaction is A + B ---> C + D

Given rate determining step is a uni-molecular with A as a sole reactant.

So the order of the reaction is 1 and is with respect to A

So rate law is r = k[A] ---(1)

Given [A]=[B] = 0.120 M And r = 0.0090 M/s

Then (1) becomes 0.0090 M/s = k (0.120M)

k = 0.075 s-1

(a) when [A] is doubled the the new rate is r' = 0.075 s-1x[2x0.120M] = 0.018 M/s

So rate doubled

(b) Since the rate of the reaction will not depend upon the concentration of B , so doubling the concentration of B , the rate will not change.

So the rate is 0.0090 M/s

(c) when [A] and [B] are increased by factor four the the new rate is r' = 0.075 s-1x[4x0.120M] =  0.036 M/s

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