Map Sam holds a lit match in front of a lens (f 25.0 cm). The distance between t

Question

Map Sam holds a lit match in front of a lens (f 25.0 cm). The distance between the match and the lens is so 37.5 cm. Answer these three questions using three signifcant figures three quesions using three signifcant figureS. Part A: Pick the selection that describes the characteristics of the image from the match. O O O real and upside down real and erect virtual and upside down virtual and erect Part B: What is the value of the image distance? Number cm Part C: If the flame is actually 1.500 cm tall, how tall is the image of the flame? (Enter your answer as a positive number.) Number em Previous NextSave And Exit

Explanation / Answer

Here ,

focal length , f = 25 cm

object distance , so = 37.5 cm

part A)

as the object is more far from the focus of lens.

the image is real and upside down.

part B)

Using Lens formula

1/f = 1/so + 1/si

1/25 = 1/37.5 + 1/si

si = 75 cm

the value of image distance is 75 cm

part C)

height of image = ho * Si/SO

height of image = 1.5 * (75/37.5)

height of image = 3 cm

the height of image is 3 cm

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