A flask is charged with 0.110 mol of A and allowed to react to formB according t
ID: 690477 • Letter: A
Question
A flask is charged with 0.110 mol of A and allowed to react to formB according to the hypothetical gas-phase reaction A(g) ---> B(g) The following data are collected : times (s) 0 40 80 120 160 moles ofA 0.110 0.071 0.044 0.026 0.025(a)Calculate the number of moles of B at each time in thetable.
What I don't understand ishow do you figure out this problem period. Should you be given atotal volume or SOMETHING to figure it out? A(g) ---> B(g) The following data are collected : times (s) 0 40 80 120 160 moles ofA 0.110 0.071 0.044 0.026 0.025
(a)Calculate the number of moles of B at each time in thetable.
What I don't understand ishow do you figure out this problem period. Should you be given atotal volume or SOMETHING to figure it out? times (s) 0 40 80 120 160 moles ofA 0.110 0.071 0.044 0.026 0.025
Explanation / Answer
According to the hypotheticalgas-phase reaction A(g) ---> B(g) At time o sec that means initiallythe number of moles of reactant A is 0.110 moles At time o sec that meansinitially the number of moles of reactant B is 0.00moles After 40 sec the number of moles of Ais 0.071 moles That means at 40 sec the number ofmoles of B is 0.110-0.071=0.039 moles After 80 sec the number of moles of A is0.044 After 80 sec the number of molesof B is 0.110-0.044= 0.066 moles After 120 sec the number of moles of A is0.026 After 120 sec the number of moles of B is0.110-0.026= 0.084 moles After 160 sec the number of molesof A is 0.025 After 140 sec the number of moles of B is0.110-0.025= 0.085 moles After 140 sec the number of moles of B is0.110-0.025= 0.085 molesRelated Questions
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