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1. when 1-iodo-1-methycyclohexane is treated with NaOCH2CH3,the more highly subs

ID: 687082 • Letter: 1

Question

1. when 1-iodo-1-methycyclohexane is treated with NaOCH2CH3,the more highly subsituted alkene product predominates. whenKOC(CH3)3 is used, the less highly subsituted alkene productpredominates.offer an explanation. 2 consider the conversion of C to D via a one-step mechanism.the activation energy of this conversion is 3 kal/mol.the energydifference between D and the trasition state of the reaction is 7kcal/mol. Estimate H degree for the reaction C D 3. consider the reaction of (CH3)3CO- with iodomethane.will the reaction rate increase, decrease or remain the same if theconcentration of iodomethane is increased? explain. 1. when 1-iodo-1-methycyclohexane is treated with NaOCH2CH3,the more highly subsituted alkene product predominates. whenKOC(CH3)3 is used, the less highly subsituted alkene productpredominates.offer an explanation. 2 consider the conversion of C to D via a one-step mechanism.the activation energy of this conversion is 3 kal/mol.the energydifference between D and the trasition state of the reaction is 7kcal/mol. Estimate H degree for the reaction C D 3. consider the reaction of (CH3)3CO- with iodomethane.will the reaction rate increase, decrease or remain the same if theconcentration of iodomethane is increased? explain.

Explanation / Answer

1) Due to the bulkiness of the Potassiumtert-butoxide, it cannot abstract theadjacent hydrogen that would give the Zaitsef product. As a result,it will attack the less hindered hydrogento produce the less substituted alkene, the Hoffmanproduct.