1. when 2-bromo-3-methyl-1-phenylbutane is treated with sodium methoxide, why is

Question

1. when 2-bromo-3-methyl-1-phenylbutane is treated with sodium methoxide, why is the major product 3-methyl-1-butene?
A. sn2 predominates over e2
B. the less substituted alkene is always more stable than the more substituted alkene
C. the newley formed double bond in this compound is conjugated with the phenyl ring
D. the bulkiness of the methoxidw results in less substituted alkene
E. e1 predominated over e2

2.

3.

4.

5

6.

7.

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9.

10.

What mechanism predominates in the reaction below? CHCH NaOCH, CH,OH Cl O SN2 SNI without rearrangement SN1 with rearrangement 0E1

Explanation / Answer

1) C. the newley formed double bond in this compound is conjugated with the phenyl ring

2) E2

3) structure 2

primary > secondary > tertiry order of SN2 order

4) Chloro methane

5) as it is SN1 reaction no change on rate of the reaction

6) 2-iodopropane

leaving group order I > Br > Cl > F

7) 1-iodo-3-methylpentane

8) 2-iodo-2-methylpentane

9) your choosen option is correct only ether will form

10) I-

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