A typical simplest-ratio formula for anthracite coal isC 52 H 16 O (s) .The stan

Question

A typical simplest-ratio formula for anthracite coal isC52H16O(s) .The standard enthalpyof formation of anthracite can be estimated at -396.4kJ/mol. Whatis the quantity of energy available from burning 100.0kg ofanthracite coal in a thermal electric power plant, according to thefollowing equation? 2C52H16O(s) +111O2(g) -----> 104CO2(g) +16H2O(g) (The answer is 3.34 x 103 MJ) A typical simplest-ratio formula for anthracite coal isC52H16O(s) .The standard enthalpyof formation of anthracite can be estimated at -396.4kJ/mol. Whatis the quantity of energy available from burning 100.0kg ofanthracite coal in a thermal electric power plant, according to thefollowing equation? 2C52H16O(s) +111O2(g) -----> 104CO2(g) +16H2O(g) (The answer is 3.34 x 103 MJ) (The answer is 3.34 x 103 MJ)

Explanation / Answer

2C52H16O(s) +111O2(g) -----> 104CO2(g) +16H2O(g) Heat of reaction, H = [ 104 (Hf(CO2) + 16 (Hf(H2O) ] -[ 2( Hf( C52H16O) ) + 111 (Hf(O2) )]                                 = [ 104 ( -393.5 kJ/mol) + 16 (-242 kJ/mol) ] - [ 2( -396.4 kJ/mol) + 111 (0) ] Solve the equation to get the value of heat given when 2 molesof coal is burnt in air. Calculate moles of coal = mass / atomic mass                                     =100 * 103 g / 12.00 g/mol                                     =8333.33 moles From the heat obtained for 2 moles, we can then calculate theheat obtained for 8333.33 moles. From the heat obtained for 2 moles, we can then calculate theheat obtained for 8333.33 moles.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.