For the reaction, Cl 2 (g) <--->2Cl (g),K c =0.0168 at 200 degrees Celcius. 0.22

Question

For the reaction, Cl2 (g) <--->2Cl (g),Kc=0.0168 at 200 degrees Celcius. 0.222 mol of Clwere placed in a 2.50L flask at 20 degrees C; no Cl2 waspresent initially. What are the equilibrium concentrations ofCl2 and Cl? <---> = Double Arrow Thanks!! For the reaction, Cl2 (g) <--->2Cl (g),Kc=0.0168 at 200 degrees Celcius. 0.222 mol of Clwere placed in a 2.50L flask at 20 degrees C; no Cl2 waspresent initially. What are the equilibrium concentrations ofCl2 and Cl? <---> = Double Arrow Thanks!!

Explanation / Answer

We Know that :         The given Reactionis :                                   Cl2 (g) <--->2Cl (g)                    intial:    0.0888              0                     change :    -x                 + 2 x                            equilibrium :    0.0888 -x      +2 x                                                             Kc    =  (2X)2 / (0.0888- X)                               X = 0.017326               The equilibrium concentration of Cl2   = 0.071474 M                  The equilibrium concentration of Cl   = 2 x0.017326                                                                            = 0.0346 M.

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