For the reaction below. Delta H degree = -542.2 kJ mol^-1 at 298 K. H_2 (g) + F_

Question

For the reaction below. Delta H degree = -542.2 kJ mol^-1 at 298 K. H_2 (g) + F_2 (g) rightarrow 2HF(g) To estimate Delta H for the reaction at 350 K. what add information would be required? C_P as a function of temperature for each reacts product. C_V as a function of temperature for each reactant and product The chemical potential at 350 K for each reactant and product The absolute entropy at 350 K for each reactant and product A constant-volume bomb calorimeter is used to determine Delta U of combustion of an unknown substance. After the calibration using benzoic acid, a student accidently used 10% more water in the bath for the combustion of the unknown. Estimate how the error will change the calculated value of AU. No change because the water bath is used to maintain adiabatic conditions. No change because the water does not participate in the reaction. The value obtained will underestimate the actual Delta U. The value obtained w ill overestimate the actual Delta U. What is the correct expression for the absolute entropy of neon? Assume that Ne forms a pure, perfect crystalline solid at zero Kelvin and has a melting point of T_m and a boiling point of T_b. S degree (2698 K) = 0 + integral^T_m_0K C_P solid dT/T + Delta_vap H/T_m + integral^T_b_T_m C_P.liquid dT/T + Delta_vap H/T_b + integral^298K_T_b C_P.vapor dT/T S degree (298K) = 0 + integral^T_b_0K C_P.solid dT/T + integral^T_b_T_m C_P.liquid dT/T + integral^298K_T_b C_P.vapor dT/T S degree (298K) = integral^298K_0K C_p dT/T S degree (298K) = 0 because neon is an element in its Standard state at 298 K.

Explanation / Answer

answer 1 ) correct option is A

Cp is a function of temperature for each reactant and product is required to calculate delta H .

answer 2) correct option is C

the value obtained will be underestimate the actual delta U

as we are using constant volume calorimetry that means it is sealed no trasfer of matter from sysytem to surrounding that is why it is reffered as constant volume .

answer 3) the correct option is D

S(298K)=0 because neon is an element in its standard state at 298 K

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