A model compound for hemeglobin \"HemeFe\" is found to bind toO2 and CO with the

Question

A model compound for hemeglobin "HemeFe" is found to bind toO2 and CO with the equilibrium constants shown below at 310 K HemeFe + O2 <--->HemeFeO2   Keq = 34 HemeFe + CO <---> HemeFeCO Keq = 860 Calculate the equilibrium constant for the followingreaction HemeFeO2 + CO <---> HemeFeCO +O2 A model compound for hemeglobin "HemeFe" is found to bind toO2 and CO with the equilibrium constants shown below at 310 K HemeFe + O2 <--->HemeFeO2   Keq = 34 HemeFe + CO <---> HemeFeCO Keq = 860 Calculate the equilibrium constant for the followingreaction HemeFeO2 + CO <---> HemeFeCO +O2 HemeFe + CO <---> HemeFeCO Keq = 860 Calculate the equilibrium constant for the followingreaction HemeFeO2 + CO <---> HemeFeCO +O2

Explanation / Answer

The resulting reaction is obtained by the substractionof the first reaction from the second reaction.           HemeFeO2  <--->      HemeFe+O2             K = 1/Keq = 1/34           HemeFe + CO<----->HemeFeCO          K = 860     -----------------------------------------------------------------      HemeFeO2  + CO <-----> HemeFeCO  +O2          K = 860/34                                                                                               =25.29

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