Part A A sample of sodium reacts completely with 0.568kg of chlorine, forming 93
ID: 596148 • Letter: P
Question
Part AA sample of sodium reacts completely with 0.568kg of chlorine, forming 936g of sodium chloride. What mass of sodium reacted?
Express your answer to three significant figures and include the appropriate units.
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 18.0g of carbon were burned in the presence of 62.3g of oxygen, 14.3g of oxygen remained unreacted. What mass of carbon dioxide was produced?
Express your answer to three significant figures and include the appropriate units.
Explanation / Answer
CH4 + 2O2 -> CO2 + 2H2O MM 16.04 g 32 g 44 g 18.02 g M/M 1 2 1 2 Moles 5.36 X 10 ^ -4 Quan. 8.6 X 10^-3 g 5.36 X 10^ -4 moles X 44 g = 2.36 X 10^ -2 g of CO2 i think this is true if that is the equation of the combustion of methane..i looked up the equation but im not completely sure Here is what I did. I found the number of moles of the CH4 based on the amount originally given. Since there is 8.36 X 10^-3 g, I divided this amount by the molar mass of CH4, which is around 16.04 g to get the number of moles. Now, in the balanced equation, the mole to mole ratio of CH4 is one because there is no coefficient before CH4, and the mole to mole ratio of the CO2 produced is also one, meaning the number of moles are the same, so you don't have to do any extra math to get the number of moles of CO2. You already know it's 5.36 X 10^ -4 moles. You multiply that number of moles by the molar mass of CO2 to get the amount in grams.
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