Part A A graduated cylinder contains 23.0 mL of water. What is the new water lev

Question

Part A A graduated cylinder contains 23.0 mL of water. What is the new water level, in milliliters, after 37.6 g of silver metal is submerged in the water? B thermometer containing 7.0 g of mercury has broken. What volume, in cubic centimeters, of mercury spilled?
Part C A fish tank holds 40. gal of water. How many kilograms of water are in the fish tank? Part A A graduated cylinder contains 23.0 mL of water. What is the new water level, in milliliters, after 37.6 g of silver metal is submerged in the water? B thermometer containing 7.0 g of mercury has broken. What volume, in cubic centimeters, of mercury spilled?
Part C A fish tank holds 40. gal of water. How many kilograms of water are in the fish tank? Part A A graduated cylinder contains 23.0 mL of water. What is the new water level, in milliliters, after 37.6 g of silver metal is submerged in the water? B thermometer containing 7.0 g of mercury has broken. What volume, in cubic centimeters, of mercury spilled?
Part C A fish tank holds 40. gal of water. How many kilograms of water are in the fish tank? Part C A fish tank holds 40. gal of water. How many kilograms of water are in the fish tank?

Explanation / Answer

PartA

Let us calculate the volume of silver

density of silver = 10.5 grams per cubic centimeter

volume = Mass / Density

Mass = 37.6 gm

Density = 10.5 gm /cm^3

substitute the values and find volume

Volume = 37.6 / 10.5 = 3.58 cm^3

Total volume = 23 + 3.58 = 26.58 ml

Part B

density of mercury = 13.56 grams per cubic centimeter

Volume = Mass / Density

Volume = 7 gm / 13.56gm / cm^3 = 0.516 cm^3

It will have the volume 0.516 cm^3

Part C

3.7854 kg = 1 Gal

Hence 40 Gal = 40 x 3.7854 = 151.416 kg

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