1.Enter your answer in the provided box. Calculate the number of moles of solute
ID: 593365 • Letter: 1
Question
1.Enter your answer in the provided box.
Calculate the number of moles of solute in 206.0 L of 0.589 M sodium cyanide.
_____ moles of solute
2.Enter your answer in the provided box.
If 11.58 mL of a standard 0.1956 M KOH solution reacts with 93.10 mL of CH3COOH solution, what is the molarity of the acid solution?
Enter your answer in the provided box.
3. Muriatic acid, an industrial grade of concentrated HCl, is used to clean masonry and cement. Its concentration is 11.7 M. For routine use, a diluted solution of 3.50 M is prepared. How many milliliters of 3.50 M muriatic acid solution contain 63.3 g of HCl?
4.Enter your answer in the provided box.
5.If 32.8 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.496 g of precipitate, what is the molarity of silver ion in the original solution?
How many total moles of ions are released when the following sample dissolves completely in water?
77.9 g of CuSO4 .5H2O:
1.Enter your answer in the provided box.
Calculate the number of moles of solute in 206.0 L of 0.589 M sodium cyanide.
_____ moles of solute
2.Enter your answer in the provided box.
If 11.58 mL of a standard 0.1956 M KOH solution reacts with 93.10 mL of CH3COOH solution, what is the molarity of the acid solution?
Enter your answer in the provided box.
3. Muriatic acid, an industrial grade of concentrated HCl, is used to clean masonry and cement. Its concentration is 11.7 M. For routine use, a diluted solution of 3.50 M is prepared. How many milliliters of 3.50 M muriatic acid solution contain 63.3 g of HCl?
4.Enter your answer in the provided box.
5.If 32.8 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.496 g of precipitate, what is the molarity of silver ion in the original solution?
How many total moles of ions are released when the following sample dissolves completely in water?
77.9 g of CuSO4 .5H2O:
Explanation / Answer
1)concentration:0.589 M
volume: 206.0 L
no of moles:?
Molarity= no of moles/volume in litres
0.589=no of moles/206.0
no of moles=0.589 x 206.0=121.334 moles
please ask the questions separately
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