is this solution correct? Why does the 12-(0.01)I2-(0.06)I3=0 go to 0.07 in the
ID: 584340 • Letter: I
Question
is this solution correct? Why does the 12-(0.01)I2-(0.06)I3=0 go to 0.07 in the second part?
Using Kirchhoff's rules, 12.0 - (0.010 0)I_1 - (0.060 0)I_3 = 0 10.0 + (1.00)I_2 - (0.060 0)I_3 = 0 and I_1 = I_2 + I_3 12.0- (0.010 0)I_2 - (0.070 0)I_3 = 0 10.0 + (1.00)I_2 - (0.060 0)I_3 = 0 Solving simultaneously, I_2 = in the dead battery and I_3 = in the starter. The currents are forward in the live battery and in the starter, relative to normal starting operation. The current is backward in the dead battery, tending to charge it up.Explanation / Answer
Yes you are absolutely right, this seems to be a printing mistake,
If i solve the original Equation which looks to be fine the answers would be -
12.0 - 0.01 * I1 - 0.06 * I3 = 0 ------1
10.0 + 1.0 I2 - 0.06 * I3 = 0 --------2
I1 = I2 + I3 ---------3
Solving these eq,
I1 = 171.67 A
I2 = 0.28 A
I3 = 171.38 A
This actually matches the answers, so that would only be a printing mistake.
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