A) on the right are two point charges Q1 = -90.0 × 10-6 C and Q2 = 50.0 × 10-6 C

Question

A) on the right are two point charges Q1 = -90.0 × 10-6 C and Q2 = 50.0 × 10-6 C separated by a distance D = 0.300 m, as shown. Calculate the potential at point A positioned d = 0.120 m to the left of Q1. Answer: _______ volts

B) Eight uncharged capacitors with equal capacitances are combined in parallel. The combination is connected to a 7.97-V battery, which charges the capacitors. The charging process involves 1.91 × 10-4 C of charge moving through the battery. Find the capacitance of each capacitor. _____F

Explanation / Answer

A)

Potential is given by

P = kQ/d

the potential at point A due to Q1 = kQ1/0.12 = 8.99*10^9*(- 90.0)*10^(-6)/0.12 = -6742500 volt

the potential at point A due to Q2 = kQ2/(0.12+0.3) = 8.99*10^9*(50.0)*10^(-6)/0.42 = 1070238.1 volt

Net potential at point A = - 6742500 + 1070238.1 = - 5672261.9 volt

B)

capacitors are connected in parallel.so

equivalent capacitance = 8*C {let capacitance of one capacitor is C F}

charge Q = Ceq*V = 8*C*7.97

given is Q is equal to 1.91*10^(-4) C so

8*C*7.97 = 1.91*10^(-4)

C = 2.99*10^(-6) F {ANSWER}

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