A) find the angular acceleration in rev/s^2? B) find the number of revolutions m

Question

A) find the angular acceleration in rev/s^2?
B) find the number of revolutions made by the motor in the 2.20 s interval.
C) how many more seconds are required for a fan to come to rest if the angular acceleration remains constant at the value calculated in part A?
Problem 9.15 Part A An electric fan is tumed off, and its angular velocity decreases uniformly from 510 rev/min to 160 rev/min in 2.20s Find the angular acceleration in rev/s rev/s? Submit My Answers Give Up Part B Find the number of revolutions made by the motor in the 2, 20 s interval. My hoswers Give Up Submit Part C How many more seconds are required for the fan to come to rest if the angular acceleration remains constant at the value calculated in part A? Submit Give L Continue

Explanation / Answer

A)

Angular acceleration is

alpha = (160-510)/2.2*60 = -2.65 m/s2

B)

Number of revolutions made is n

1 = 2n1 = 2 x 3.14 x 510/60 = 53.38rad/sec
& 2 = 2 x 3.14 x (160/60) = 16.74 rad/sec

By 2^2 = 1^2 - 2
=>2 x 2.65 x = (53.38)^2 - (16.74)^2
=> = 484.7 rad = 484.7 x 180/ = 27786
=>by n x 360= 27786
=>n =77 revolutions

C)

By 2 = 1 - t
=>2.65t = 16.74-0
=>t =6.31 sec

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