tem 7 Part A Balance each of the following redox reactions occurring in acidic s

Question

tem 7 Part A Balance each of the following redox reactions occurring in acidic solution. Cr20,2 (aq)+Cu (aq)+Cr(aq)Cu (ag) Express your answer as a chemical equation. ldentify all of the phases in your answer ? Submit My Answers Give Up Part B CIO, (aq) + Cl-(aq) CIOg (aq) + Cl2(g) Express your answer as a chemical equation. Identify all of the phases in your answer. ? Submit My Answers Give Up Part C NOS (aq) + Sn2+ (aq) Sn4+ (aq) + NO(g) Express your answer as a chemical equation. Identify all of the phases in your answe

Explanation / Answer

First, define the “ACIDIC” solution/conditions as H+ presence and

Basic solution implies OH- once it is balanced.

Also; note that ALL species must be balanced, as well as charges

Typical steps:

1) split half redox cells

CrO7-2 = Cr+3

Cu+ = Cu+2

2) balance atoms other than O,H

Cr2O7-2 = 2Cr+3

Cu+ = Cu+2

3) balance O by adding H2O

Cr2O7-2 = 2Cr+3 + 7H2O

Cu+ = Cu+2

4) balance H by adding H+

14H+ + Cr2O7-2 = 2Cr+3 + 7H2O

Cu+ = Cu+2

5) balance charge by adding e-

6e- + 14H+ + Cr2O7-2 = 2Cr+3 + 7H2O

Cu+ = Cu+2 + 2e-

6) balance e- by multiplying by the Greatest common divisor

6e- + 14H+ + Cr2O7-2 = 2Cr+3 + 7H2O

3Cu+ = 3Cu+2 + 6e-

7) Add both equations

3Cu+ + 6e- + 14H+ + Cr2O7-2 = 2Cr+3 + 7H2O + 3Cu+2 + 6e-

8) simplify repeating elements, H+, H2O, and e- typically

3Cu+ + 14H+ + Cr2O7-2 = 2Cr+3 + 7H2O + 3Cu+2

B)

repeat

ClO4- = ClO3-

Cl- = Cl2

balance Cl

ClO4- = ClO3-

2Cl- = Cl2

balance O

ClO4- = ClO3- + H2O

2Cl- = Cl2

balance H+

2H+ + ClO4- = ClO3- + H2O

2Cl- = Cl2

balance charge

2e- + 2H+ + ClO4- = ClO3- + H2O

2Cl- = Cl2 + 2e-

add all

2Cl- + 2e- + 2H+ + ClO4- = ClO3- + H2O +  Cl2 + 2e-

simplify

2Cl- + 2H+ + ClO4- = ClO3- + H2O +  Cl2

C)

split

NO3- = NO

Sn+2 = Sn+4

balance O

NO3- = NO + 2H2O

Sn+2 = Sn+4

balance H

4H+ + NO3- = NO + 2H2O

Sn+2 = Sn+4

balance charge

3e- + 4H+ + NO3- = NO + 2H2O

Sn+2 = Sn+4 + 2e-

balance e-

6e- + 8H+ + 2NO3- = 2NO + 4H2O

3Sn+2 = 3Sn+4 + 6e-

add all

3Sn+2 + 6e- + 8H+ + 2NO3- = 2NO + 4H2O + 3Sn+4 + 6e-

simplify

3Sn+2 + 8H+ + 2NO3- = 2NO + 4H2O + 3Sn+4

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