ted n metal Ions (such as Mn or Fe). 2 H2O2(aq)-2 H20(+ Oz(g) what e tu e o, po
ID: 1033858 • Letter: T
Question
ted n metal Ions (such as Mn or Fe). 2 H2O2(aq)-2 H20(+ Oz(g) what e tu e o, po e os n eolected at 27 C and 746 ton, would be generated by decomposition of i 20 g o, a so.0% by mass hydrogen peroxide solution? Ignore any water vapor that may be present. Rnad the eBook 5 Section 4 S03, is in enormous quantities each year for use in the synthesis of sulfuric acid. s(s) + 02(9) s02(9) 2 S0209)02(9)2 S03(9) What volume of O2(a) at 3so."C and a pressure of 5.25 atm is needed to completely convert 5.15 g of sulfur to sulfur trioxide?Explanation / Answer
Molar mass of H2O2= 34 g/mole, mass of H2O2 solution=120 gm, mass of H2O2=50%
Mass of H2O2 in the solution = 120*50/100= 60 gm,
Moles of H2O2= mass/molar mass= 60/34 = 1.764
From the reaction 2H2O2(aq) ------->2H2O(l)+O2(g)
2 moles of H2O2 generates 1 mole of O2
1.764 moles of H2O2 generates 1.764/2= 0.882 moles, hence n= 0.882 for using gas law
PV= nRT is gas law equation, if R= 0.0821 L.atm/mole.K, P has to be in atm, T has to be inK. Then V will be in litres.
Given P= 760 torr, 1 atm= 760 Torr, P= 1atm, T= 27 deg.c= 27+273= 300K
Hence V= nRT/P= 0.882*0.0821*300/1=21.72 L
2.
The reaction is S(s)+ O2(g)-->SO2(g)- (1). Eq.1*2 gives 2S(s)+O2(g) -----à>SO2(g) -1A
2SO2(g)+ O2(g) ------->2SO3(g)- (2)
Eq.1A+Eq.2 gives 2S+3O2 ---->2SO3
Hence 2 moles of SO3 requires 3 moles of O2
Moles of SO3= mass/molar mass= 5.15/80 =0.064
Hence moles of O2= (3/2)*0.064=0.096, hence n= 0.096,
PV= nRT is gas law equation, if R= 0.0821 L.atm/mole.K, P has to be in atm, T has to be inK. Then V will be in litres.
P= 5.25 atm, T= 350 deg.c= 350+273=623K, B= nRT/P= 0.096*0.0821*623/5.25=0.935L
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