ted : A 4.9 105-kg Is Assignment-3 Begin Date: 9/18/2017 12:00:00 i AM- -Due Dat

Question

ted : A 4.9 105-kg Is Assignment-3 Begin Date: 9/18/2017 12:00:00 i AM- -Due Date: 9/25/2017 11:59:00 PM End Date:9/26/2017 11:59:00 PM (20 %) Problem 3: A 52·105-kg rocket is accelerating straight up. Its engines produce 1.4 . 107 N of thrust, and air resistance is 4.45 0106 N Randomized Variables m = 5.2 . 105-kg f= 1.4 . 107x fr=4.45 . 106 N what is the rocket's acceleration, using a coordinate system where up is positive? sinO | cos() | tan() | | ( ) 7| 8|9| Attempts remai (3% per attemp detailed view atan0 acotan sinh0 °Degrees Radians Hint Feedback: deduction per feedback. Hints. I % deduction per hint. Hints remaining:- Al ©2017Expert TA.u.c

Explanation / Answer

F = m a

Net force F = T - f - m g

ma = T - f - mg

a = (T - f - mg) / m

a = (1.4 * 107 - 4.45 * 106 - (5.2 * 105 * 9.8)) / 5.2 * 105

acceleration a = 8.57 m/s2

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