Part A As a technician in a large pharmaceutical research firm, you need to prod

Question

Part A As a technician in a large pharmaceutical research firm, you need to produce 100. mL, of a potassium dihydrogen phosphate buffer solution of pH 7.01. The pK, of H2POs is 7.21 You have the following supplies: 2.00 L of 1.00 M KH, PO, stock solution, 1.50 L of 1.00 M K2HPO4 stock solution, and a carboy of pure distilled H2 O How much 1.00 M KH,PO, will you need to make this solution? (Assume addlitve volumes.) Express your answer to three significant digits with the appropriate units. Hints Volume of KH2PO4 needed= 1 Value Units Submit My Answers Give Up

Explanation / Answer

pH of phosphate buffer = pka2 + log(HPO4^-2/H2PO4^-)

   pka2 phosphate buffer = 7.21

Total volume = 100 ml

no of mol of HPO4^-2 = M*V = 1*(X) mol

no of mol of H2PO4^- = M*V = 1*(100-X) mol

7.01 = 7.21 +log(x/(1*100-x))

x = 38.7 ml

volume of 1 M KH2PO4 required = 100-38.7 = 61.3 ml

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