Part A As a technician in a large pharmaceutical research firm, you need to prod
ID: 612341 • Letter: P
Question
Part A As a technician in a large pharmaceutical research firm, you need to produce 450.mL of 1.00 M a phosphate buffer solution of m pH = 7.16. The { m p}K_{ m a} of m {H_2PO_4}^- is 7.21. You have 2.00 m L of 1.00 m M~KH_2PO_4 solution and 1.50 m L of 1.00 m M~K_2HPO_4 solution, as well as a carboy of pure distilled m H_2O. How much 1.00 m M~KH_2PO_4 will you need to make this solution? Express your answer numerically in milliliters to three significant figures. Volume of m KH_2PO_4 needed = m mL PART B The Henderson-Hasselbalch equation in medicine Carbon dioxide ( m CO_2) and bicarbonate ( m {HCO_3}^-) concentrations in the bloodstream are physiologically controlled to keep blood pH constant at a normal value of 7.4. Physicians use the following modified form of the Henderson-Hasselbalch equation to track changes in blood pH: m pH = p{it K}_a + log rac{[{HCO_3}^-]}{(0.030)({it P}_{CO_2})} where m [{HCO_3}^-] is given in millimoles/liter and the arterial blood partial pressure of m CO_2 is given in m mmHg. The { m p}K_{ m a} of carbonic acid is 6.1. Hyperventilation causes a physiological state in which the concentration of m CO_2 in the bloodstream drops. The drop in the partial pressure of m CO_2 constricts arteries and reduces blood flow to the brain, causing dizziness or even fainting. Part B If the normal physiological concentration of m {HCO_3}^- is 24 { m m}M, what is the pH of blood if P_{ m CO_2} drops to 24.0mmHg ? Express your answer numerically using one decimal place. pH =Explanation / Answer
you have to solve 2 equations..because you have 2 unknowns. (volume of base)/(volume of acid) = 0.741 and (volume of base) + (volume of acid) =.45L so solve for one variable in terms of the other and substitute and you can find the answer easily...Hopefully this helps.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.