A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dis

Question

A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in Hcl. After the fillers were filtered out, the HCl was neutralized by adding sodium carbonate. The resulting precipitate was pure calcium carbonate (with the fillers removed). The solid calcium carbonate was collected on a watch glass that had a mass of 46.719 g when empty. After the calcium carbonate had been allowed to dry, the mass of the watch glass plus product was found to be 47.659 g 1. What is the mass of pure calcium carbonate product collected at the 2. Calculate the mass & calcium carbonate in the tablet. 3. Calculate the mass percent calcium in calcium carbonate. This end of the experiment? calculation is theoretical and is independent of the data provided 4. Calculate the number of grams of calcium that were in the tablet. (Hint: this can be obtained using the answers to questions 1 and 3.) 5

Explanation / Answer

1. Weight of the empty watch glass = 46.719 g

Weight of the watch glass + calcium carbonate = 47.659 g

Weight of Calcium Carbonate = 47,659 - 46.719

= 0.94 g

Mass of the pure calcium carbonate collected at the end of the experiment = 0.94 g

2. Mass % of calcium carbonate in tablet = wt. of calcium carbonate/ wt. of the tablet X 100

= 0.94/1.631*100

=57.63335

It is 57.63335%

3. Mol.wt. of calcium carbonate is 100.086

Mol wt of calcium is 40.078

% of calcium in calcium carbonate = 40.078/100.086*100

=40.044

4. 100.086 g of calcium carbonate has 40.044 g of calcium

Therefore 0.96 g of pure calcium cabonate has 0.376 g of calcium. ( 0.96*40.044/100.086)

0.376 g of calcium is present in 1.631 g of the tablet.

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