Need answers to all the three please. Q1. Assuming the following reaction procee

Question

Need answers to all the three please.

Q1. Assuming the following reaction proceeds in the forward direction, Sr(s) + Cu2+(aq) Sr2+(aq) + Cu(s) a) Cu2(aq) is oxidized and Sr (s) is reduced. b) Cu (aq) is oxidized and Sr2 (aq) is reduced. c) Sr (s) is oxidized and Cu2 (aq) is reduced. d) Cu(s) is oxidized and Sr (s) is reduced. Q2. What is the oxidation state of molybdenum in Mo04? a) +6 b) +4 c) +7 d) Q3. Which of the following happens when VO2 reacts to form Vo a) VO2* acts as an oxidizing agent. b) The oxidation state of vanadium increases. c) VO2 is reduced. d) The oxidation state of oxygen decreases

Explanation / Answer

1)
Sr is oxidised from 0 oxidation state to +2 oxidation state
Cu is reduced from +2 to 0 oxidation state
Answer: c

2)

Oxidation number of O = -2

lets the oxidation number of Mo be x

use:
4* oxidation number (O) + 1* oxidation number (Mo) = net charge
4*(-2)+1* x = -2
-8 + 1 * x = -2
x = 6
So oxidation number of Mo = +6
Answer: a

3)
oxidation state of V in Vo 2+ is +4
oxidation state of V in Vo2 + is +5
Answer: c

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