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To determine the ammonia concentration in a sample of lake water, you mix 10.0 m

ID: 541463 • Letter: T

Question

To determine the ammonia concentration in a sample of lake water, you mix 10.0 mL of lake water with 5 mL of phenol solution and 2 mL of sodium hypochlorite solution and dilute to 25.0 mL in a volumetric flask (sample A). To a second 10.0 mL solution of lake water you add 5 mL of phenol, 2 mL of sodium hypochlorite, and 2.50 mL of a 5.50 × 10–4 M ammonia solution and dilute to 25.0 mL (sample B). As a reagent blank, you mix 10.0 mL of distilled water with 5 mL of phenol, 2 mL of sodium hypochlorite and dilute to 25.0 mL (sample C). You measure the following absorbances using a 1.00 cm cuvet:

Sample: Absorbance: (625nm)

A 0.479

B 0.726

C 0.045

What is the molar absorptivity () of the indophenol product, and what is the concentration of ammonia in the lake water?

University of Kentucky - C Chegg Study | Guided Scx www.saplinglearning.com/ibiscms/mod/ibis/view.php?id:4057860 : Apps Studentloans.gov AT&T; () canvas-, myUK CHE Lab E REEF O Target M connectWileyPLUS A gas bil D New Tab Sapling Learning Jump to... View Profile macmilan learning Print Periodic Table Logout Question 8 of 10 Points Possible: 10 Mapoh Grade Category Graded Description Policies: Treatment of ammonia with phenol in the presence of hypochlorite yields indophenol, a blue product absorbing light at 625 nm, which can be used for the spectrophotometric determination of ammonia You can check your answers. You can view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up You lose 5% of the points available to each answer attempt at that answer indophenol anion 6 100 determine the ammonia concentration in a mL of phenol solution and 2 mL of sodium hy le of lake water, you mix 10.0 mL of lake water with sclution and dilute to 25.0 mL in a volumetric fiask (sample A) To a second 10.0 mL solution of lake water you add 5 mL of phenol, 2 mL of sodium hypochlorite, and 2.50 mL of a 5.50 x 10 M ammonia solution and dilute to 25.0 mL (sample B). As a t blank, you mix 10.0 mL of distilled water with 5 mL of phenol, 2 mL of sodium hypochlorite and dilute to 25.0 mL (sample C). You measure the following absorbances using a 1.00 cm cuvet: in your question for each i ncorrect (625 nm) 0.479 0.726 0.045 O eTextbook O Help With This Topic What is the molar absorptivity (e) of the indophenol product, and what is the concentration of ammonia in the lake water? O Web Help&Videos; ake water O Technical Support and Bug Reports Previaus Give Up & View Solutian Check Answer Next Ex Hint 11:57 AM ID ^DQs 10/16/2017

Explanation / Answer

Sample A = 10 mL lake water + 5 mL Phenol+ 2 mL Sodium Hypoclorite Sample

SampleB = 10 mL lake water + 5 mL Phenol+ 2 mL Sodium Hypoclorite + 2.5 mL 5.5 x 10-4 M NH3 Sample + sandard Soltion

Sample C = 10 mL distilled water + 5 mL Phenol+ 2 mL Sodium Hypoclorite Blank

       OD

Sample A         Sample                                          0. 479

SampleB          Sample + Standard Solution            0. 726

Sample C        Blank                                             0.045

To get the OD of standard solution alone = ODA-ODB = 0.726 - 0.479 = 0.247

Given standard NH3 solution concentration is 5.5 x 10-4 M and we have taken 2.5 mL and diluted to 25 mL.

Therefore, the net concentration of [NH3] from standard solution = 2.5 mL x 5.5x10-4 M/ 25 mL = 5.5 x 10-5 M

From Beers lamberts law;

OD = e.c.l

0.247 = e x 5.5 x 10-5 M x 1 cm

e = 4.5 x 103 M-1 cm-1

Ammonia concentration in the lake water :

ODsample = ODA - ODC = 0.478 - 0.045 = 0.433

Again from Beers law;

ODsample = e.c.l

0.433= 4.5x103 M-1cm-1 x C x 1 cm

[NH3] = C = 9.62x 10-5 M

Therefore, Answer : Molar absorptivity () of the indophenol = 4.5 x 103 M-1cm-1

The concentration of ammonia in the lake water [NH3]lake water = 9.62 x 10-5 M

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