This question has multiple parts. Work all the parts to get the most points. Ide

Question

This question has multiple parts. Work all the parts to get the most points. Identify the principal conjugate acid/base pair and calculate the ratio between them in a solution that is buffered to pH 8.70 and contains This problem requires values in your textbook's specific appendices, which you can access through the OWLv2 MindTap Reader. You should not use the OWLv2 References' Tables to answer this question as the values will not match. Simplify your answer completely.) H2S Principal conjugate acid HAS Principal conjugate base HS Principal conjugate acid Ratio Principal conjugate base to ethylenediamine dihydrochloride. Principal conjugate acid NH 2 HANH Principal conjugate base NH2C2H4NH2 Principal conjugate acid] Ratio Principal coniugate basel

Explanation / Answer

Pka = 7

PH   = Pka + log[HS-]/H2S]

8.7   = 7 + log[HS-]/H2S]

log[HS-]/H2S] = 8.7-7

log[HS-]/H2S]    = 1.7

[HS-]/H2S]   = 10^1.7

[HS-]/H2S]    = 50.12

[H2S]/[HS-]   = 1/50.12

Pkb = 10.81

PH = 8.7

POH = 14-PH

          = 14-8.7   = 5.3

POH = Pkb + log[NH2 C2H4 NH3+]/[NH2 C2H4 NH2]

5.3      = 10.81 + log[NH2 C2H4 NH3+]/[NH2 C2H4 NH2]

log[NH2 C2H4 NH3+]/[NH2 C2H4 NH2]   = 5.3-10.81

log[NH2 C2H4 NH3+]/[NH2 C2H4 NH2]   = -5.51

[NH2 C2H4 NH3+]/[NH2 C2H4 NH2]        = 10^-5.51

[NH2 C2H4 NH3+]/[NH2 C2H4 NH2]     = 3.1*10^-6

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