This question has been answered but the given answer doesn\'t fit the answer sel
ID: 249263 • Letter: T
Question
This question has been answered but the given answer doesn't fit the answer selections that are given with the question
(1) 1.75e^-6
(2) 2.35e6^-6
(3) 3.51e^-6
(4) 1.75e^-5
(5) 2.35e^-5
(6)5.10e^-5
and the answer selections for 3A are:
(1) 1.64e^-5
(2) 2.45e^-5
(3) 3.11e^-5
(4) 3.65e^-5
The answer given on here 7 years ago doesn't even come close, though I got the same. So either the selections are wrong or my calculations and that of the person who previously provided an answer to this question are wrong. Help.
Explanation / Answer
Flux = ( Density of flux ) x (A)
Use Ampere's Law
B = (u0) I /(2pi)r
u0 = 4pi x 10^-7 T m / A
B = (4pi x 10^-7)(5)/2(3.14)(0.03)
magnetic flux density of 5A current is
B = 3.33 x 10^-5 Tesla = 3.33 x 10^-5 Weber/m^2
Flux density due to the 3 A current only is
B =2.99 x 10^-5 Webers/m^2
use right hand rule the B field points Out of the Page.
since they both point out of the page, so the total flux density is
B = (3.33 x 10^-5 + 2.99 x 10^-5)
B= 6.32 X 10^-5 Wb/m^2
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.