The reaction in question will be carried out in a calorimeter. The volume of the

Question

The reaction in question will be carried out in a calorimeter. The volume of the chamber inside is 2.00 L. Experiment starts by evacuating the chamber to 0.00 kPa. Then oxygen gas is filled into the chamber till pressure 200. kPa. Then hydrogen gas is filled into the same chamber until total pressure 400. kPa. The oxygen and hydrogen mixture is ignited by a spark with 3.00 kJ energy. Calculate the total pressure inside the chamber after reaction. (The heat capacity of this calorimeter is 944.12 J/K. If other constants or equations are needed, you may obtain them from any resources but cite the resource in the discussion board.) 1. Explain the area of chemistry that this problem relates to and its importance. 2. What equations do you think you will be using to solve this problem? 3. Suggest a strategy to solve this problem. The reaction in question will be carried out in a calorimeter. The volume of the chamber inside is 2.00 L. Experiment starts by evacuating the chamber to 0.00 kPa. Then oxygen gas is filled into the chamber till pressure 200. kPa. Then hydrogen gas is filled into the same chamber until total pressure 400. kPa. The oxygen and hydrogen mixture is ignited by a spark with 3.00 kJ energy. Calculate the total pressure inside the chamber after reaction. (The heat capacity of this calorimeter is 944.12 J/K. If other constants or equations are needed, you may obtain them from any resources but cite the resource in the discussion board.) 1. Explain the area of chemistry that this problem relates to and its importance. 2. What equations do you think you will be using to solve this problem? 3. Suggest a strategy to solve this problem. 1. Explain the area of chemistry that this problem relates to and its importance. 2. What equations do you think you will be using to solve this problem? 3. Suggest a strategy to solve this problem. 1. Explain the area of chemistry that this problem relates to and its importance. 2. What equations do you think you will be using to solve this problem? 3. Suggest a strategy to solve this problem.

Explanation / Answer

Ans1 This problem is realted to ideal gas law. PV = nRT ( Physical Chemistry)

Ans 2: Steps are as follow:

H2 will require 100 kPa O2 to react completely; you have that much so H2 must be the limiting reagent. Next, you aren't given mols but you have P. In PV = nRT, T isn't given but it is constant, R is a constant, volume isn't given but it is constant. That means P is proportional to n; therefore, we can use kPa pressure as if it were mols.
Ans 3

.....2H2 + O2 ==> 2H2O
I....200...200.....0
C...-200..-100....+200
E.....0....100....200
So total P is 100 + 200 = 300kPa.

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