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The reaction below has an equilibrium constant K p=2.2×106 at 298 K. 2COF2(g)CO2

ID: 489305 • Letter: T

Question

The reaction below has an equilibrium constant Kp=2.2×106 at 298 K.
2COF2(g)CO2(g)+CF4(g)

Calculate Kp for the reaction below.
23COF2(g)13CO2(g)+13CF4(g)

Exercise 14.28 with feedback The reaction below has an equilibrium constant Kp 2.2 x 106 at 298 K 2 COF2 (g) CO2 (g) CF4 (g) You may want to reference (D page section 14.3 while completing this problem. Part B Calculate Kp for the reaction below 4 COF2 (g) CO2 (g) t CF4 (g) Express your answer using two significant figures AE Submit My Answers Give U

Explanation / Answer

kp for new reaction

2x3COF2(g)1x3CO2(g)+1x3CF4(g)
6COF2(g)3CO2(g)+3CF4(g)

is (2.2 x 10^6)^3

=1.065 x 10^19

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