The reaction below has an equilibrium constant K p=2.2×106 at 298 K. 2COF2(g)CO2
ID: 489305 • Letter: T
Question
The reaction below has an equilibrium constant Kp=2.2×106 at 298 K.
2COF2(g)CO2(g)+CF4(g)
Calculate Kp for the reaction below.
23COF2(g)13CO2(g)+13CF4(g)
Explanation / Answer
kp for new reaction
2x3COF2(g)1x3CO2(g)+1x3CF4(g)
6COF2(g)3CO2(g)+3CF4(g)
is (2.2 x 10^6)^3
=1.065 x 10^19
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